Reputation: 21
I have String
var t = '@qf$q>@gf';
and array of separators
var s = '@$>';
I would like to have a function which returns:
var a = f(t,s);
// a is array = ["@","qf","$","q",">","@","gf"];
Can you help me ?
Upvotes: 2
Views: 97
Reputation: 15365
Here is your code:
var t = '@qf$q>@gf';
var s = '@$>';
var finalArray = [];
var tmpString = '';
var found = false;
for (var i=0; i<t.length; i++) {
for (var j=0; j<s.length; j++) {
if (t[i] == s[j]) {
found = true;
if (tmpString != '') {
finalArray.push(tmpString);
}
finalArray.push(t[i]);
tmpString = '';
}
}
if (!found) {
tmpString += t[i];
}
found = false;
}
if (tmpString != '') {
finalArray.push(tmpString);
}
It will output:
["@", "qf", "$", "q", ">", "@", "gf"]
Here is the associated jsFiddle: http://jsfiddle.net/Cf8LA/
var t = '@qf$q>@gf';
var s = '@$>';
var finalArray = [];
var tmpString = '';
for (var i=0; i<t.length; i++) {
if (s.indexOf(t[i]) >= 0) {
if (tmpString != '') {
finalArray.push(tmpString);
}
finalArray.push(t[i]);
tmpString = '';
} else {
tmpString += t[i];
}
}
if (tmpString != '') {
finalArray.push(tmpString);
}
Updated jsFiddle here: http://jsfiddle.net/Cf8LA/1/
Upvotes: 1
Reputation: 655219
You can use a regular expression:
'@qf$q>@gf'.match(/[@$>]|[^@$>]+/g)
The regular expression /[@$>]|[^@$>]+/g
matches all occurrences of either a single separator character ([@$>]
) or any sequence of one or more non-separator characters ([^@$>]+
).
Upvotes: 3