Reputation: 741
Here is my data context:
Photos (ID, Title)
Users (ID, FullName)
Ratings (PhotoID, UserID, Value, Date)
Business rules:
I want to select the top rated photos by day in the last let's say 3 days. So which photo got the best rating today, yesterday and the day before yesterday? I would like to make the number of days variable if it possible. I have to display the last N days only they rated excluding empty days.
I would like to get the photos in a single query/result because I want to bind it to a ListView to display them on a web form.
I've started this way:
DECLARE @days INT = 3
SELECT TOP (@days) ... FROM Ratings
INNER JOIN Photos ON Photos.ID = Ratings.PhotoID
GROUP BY DATEDIFF(day, [Date], CURRENT_TIMESTAMP)
ORDER BY DATEDIFF(day, [Date], CURRENT_TIMESTAMP) DESC
How can I group my groups by PhotoID, order them by SUM(Value) and select the first one from each group? Thank you very much for your help.
Upvotes: 0
Views: 211
Reputation: 14944
SELECT Date, TotalRating, Photos.*
FROM Photos
INNER JOIN
(SELECT ROW_NUMBER() OVER (ORDER BY Date DESC) AS RowNumber,
PhotoID, Date, TotalRating
FROM (SELECT ROW_NUMBER() OVER (PARTITION BY Date, ORDER BY TotalRating DESC) AS inRowNumber,
PhotoID, Date, TotalRating
FROM (SELECT PhotoID, Date, SUM(Value) AS TotalRating
FROM Photos
GROUP BY PhotoID, Date
HAVING SUM(Value) > 0 ) t)
WHERE inRowNumber = 1) t ON Photos.Id = t.PhotoID
WHERE RowNumber <= @days
Upvotes: 2