CODEWITHSUNDEEP
linuxbash
Aristarhys
Aristarhys

Reputation: 2122

String replacement in bash - bad substitution error

I newbie in bash scripting but i don't uderstand why it's not work

#!/bin/bash
foo=foobarfoobar
echo ${foo//bar/baz}

bad substitution error on line 3

Upvotes: 14

Views: 52232

Answers (2)

Chris
Chris

Reputation: 10455

That substitution works fine in Bash 4.2.8 (and looks fine according to the documentation).

My best guess would be that you're not actually using Bash - how are you invoking the script? If you're doing sh script.sh you may well be running it with Dash or something similar (and Dash does indeed give a substitution error on line 3). Try explicitly running it with Bash (bash script.sh).

If it turns out you are actually using Dash, there's some useful information on the differences and how to go back to using Bash (if you want to) here: https://wiki.ubuntu.com/DashAsBinSh

Upvotes: 52

Max Spencer
Max Spencer

Reputation: 1719

$ foo=foobarfoobar
$ echo ${foo}/bar/baz
foobarfoobar/bar/baz

Just that you have the braces in the wrong place, but then I am no expert at BASH, so perhaps this isn't the effect you're going for..

Upvotes: -2

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