CODEWITHSUNDEEP
xslt
chernevik
chernevik

Reputation: 4000

XSLT to get parent of node with a particular value

What is the XSLT to get a parent node based on the value of the child?

My xml:

<cast>
  <character>
    <name>Bugs</name>
    <id>1</id>
  </character>
  <character>
    <name>Daffy</name>
    <id>2</id>
  </character>

I have tried this:

<xsl:template match="/cast/character/id">
    <xsl:if test="text()=1">
        <xsl:apply-templates select="../self" mode='copier'/>
    </xsl:if>
</xsl:template>

<xsl:template match="*" mode='copier'>
    <xsl:apply-templates />
</xsl:template>

But this outputs the text of every node in the document.

EDIT: I have to output XML here, I'm planning to extend this to XML generation

Upvotes: 1

Views: 1929

Answers (3)

Dimitre Novatchev
Dimitre Novatchev

Reputation: 243449

Just use:

<xsl:apply-templates select="/*/character[id=1]"/>

or, if the wanted node should just be copied with no further processing:

<xsl:copy-of select="/*/character[id=1]"/>

Upvotes: 1

Sunil
Sunil

Reputation: 1248

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/cast/character">
     <xsl:if test="id=1">
        <xsl:copy-of select="." />
     </xsl:if>
  </xsl:template>
</xsl:stylesheet>

Not able to add a comment. Hence put it here

Upvotes: 0

Jollymorphic
Jollymorphic

Reputation: 3530

I believe you're printing everything because the processor starts matching at the root and the only template you specify is for id elements, so things get copied by default. Try this:

<stylesheet xmlns="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <output method="text" />
    <template match="/">
        <apply-templates select="//id" />
    </template>
    <template match="id">
        <if test="text()='1'">
            <value-of select=".." />
        </if>
    </template>
</stylesheet>

Or if you just want the character name, you could replace the select attribute value in the value-of element with "../name".

Upvotes: 1

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