CODEWITHSUNDEEP
phphtml
gf3
gf3

Reputation: 1

PHP array created through html form only stores last element

I'm looping a question for the user with different numerical values for $i. They will input a quantity in the html form that is also looped. Upon them clicking submit, I would like to have an array (with the key ranging form [0] onwards) that stores their response to each particular variant of the question. However, with the code I have written, I only manage to store their last input with the key [0] as if it was the first element of the array. All the previous answers seem to be lost when I call print_r. Please, I would really appreciate it if anyone could point out why this is happening or how I could fix it.

<?php

    for ($i=2; $i<=10; $i++) 

    {
        print "question $i";

        echo"<form action=\"mysqlranked.php\" method=\"post\">
          <input type=\"text\" name=\"pools[]\" value=\"0\" maxlength=\"2\" size=\"2\">
          </form>
          <br>";
    }

    print "
    <form>
    <input type=\"submit\" name=\"formSubmit\" value=\"Submit\">
    </form>";

    if (isset($_POST["formSubmit"]))
    {
        $var = $_POST["pools"];
    }

    print_r($var);

?>

Upvotes: 0

Views: 746

Answers (4)

krishna
krishna

Reputation: 960

you may use array_push($arrayName, $elementToBePushed);

Upvotes: 0

Moon
Moon

Reputation: 35265

You should not have a new form tag for every question.

Try the code below:

<form action="mysqlranked.php" method="post">

<?php
    for ($i = 2; $i <= 10; $i++)
    {
        print "question $i";
?>

    <input type="text" name="pools[]" value="0" maxlength="2" size="2">

<?php
    }
?>

    <input type="submit" name="formSubmit" value="Submit">
</form>

<?php
    if (isset($_POST["formSubmit"]))
    {
        $var = $_POST["pools"];
    }

    print_r($var);
?>

Upvotes: 1

Pradeep Singh
Pradeep Singh

Reputation: 3634

    <?php

        for ($i=2; $i<=10; $i++) 

        {
            print "question $i";

            echo"<form action=\"mysqlranked.php\" method=\"post\">
              <input type=\"text\" name=\"pools[]\" value=\"0\" maxlength=\"2\" size=\"2\">

              <br>";
        }

        print "

        <input type=\"submit\" name=\"formSubmit\" value=\"Submit\">
        </form>";

     if (isset($_POST["formSubmit"])) 
        {

                for($counter=0;$counter<count($_POST["pools"]);$counter++)
                {
                    $var = $_POST['pools'][$counter]

                }

         }
print_r($var);

    ?>

Upvotes: 0

mowwwalker
mowwwalker

Reputation: 17362

You had each of your inputs in a new form and the submit button in its own form as well. I fixed it for you:

<?php

    echo "<form action=\"mysqlranked.php\" method=\"post\">";
    for ($i=2; $i<=10; $i++) 

    {
        print "question $i";

        echo"
          <input type=\"text\" name=\"pools[]\" value=\"0\" maxlength=\"2\" size=\"2\">

          <br>";
    }

    print "
    <input type=\"submit\" name=\"formSubmit\" value=\"Submit\">
    ";
    echo "</form>";
    if (isset($_POST["formSubmit"]))
    {
        $var = $_POST["pools"];
    }

    print_r($var);

?>

Let me know if it works.

Upvotes: 1

Related Questions