CODEWITHSUNDEEP
javaandroidsockets
Anh Tuan
Anh Tuan

Reputation: 1730

Android Socket-ready detection?

I'm programming an Android application allows to send messages between devices which are connected in the same local network. I've finished the socket programming part, each device can be a server or a client, one client only allow to connect with one server at a time (and vice versa). The problem is I need to know the IP address of the server I want to connect, then input it by hand on the client side.

I'm trying to establish a feature like in Multiplayer mode of game: you press "Show" button, and all the hosts (in my app they are the servers) which are avaiable will be displayed, then I can choose the host I want. But I have no idea how to achieve it, or where to start.

Any help will be appreciated. Thank you very much!

Upvotes: 0

Views: 198

Answers (1)

Ovidiu Latcu
Ovidiu Latcu

Reputation: 72321

You should also create a DatagramSocket which will be used for broadcasting, on a different port, and every device that wants to be an Server should broadcast a packet with it's ip. You should look at All about Datagrams altough it does not contain an example of broadcast. For example to send a broadcast you should take a look at the following code :

DatagramSocket mServerSocket = new DatagramSocket(PORT);
InetAddress  broadcastAddress=InetAddress.getByName("255.255.255.255");
byte[] data=new byte[1024];
data="your_data_string_example".getBytes();
DatagramPacket packet=new DatagramPacket(sendData,
                            sendData.length,broadcastAddress,PORT);
mServerSocket.setBroadcast(true);
mServerSocket.send(packet);

Upvotes: 1

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