CODEWITHSUNDEEP
c#winformsmaskedtextbox
RAGAVAN
RAGAVAN

Reputation: 33

Why Masked Textbox Not Working 00-00-1900?

I am new to WinForms.

When I am trying to implement the masked text box, I got one error.

I want a mask of 00-00-1900 where 00 handle any number, but 19 is fixed and cannot be overwritten by the user. How do I do that?

Examples of valid input are 19-12-1988 and 12-01-1958.

Upvotes: 1

Views: 1788

Answers (3)

CodesInChaos
CodesInChaos

Reputation: 108810

0 Digit, required. This element will accept any single digit between 0 and 9.

9 Digit or space, optional.

\ Escape. Escapes a mask character, turning it into a literal. "\" is the escape sequence for a backslash.

http://msdn.microsoft.com/en-us/library/system.windows.forms.maskedtextbox.mask.aspx

Since 9 is a special character, but you want to treat it as a literal, you need to escape it with \.

So I guess your mask needs to be 00-00-1\900 which I'd write as @"00-00-1\900" in C# code.

Upvotes: 2

user1173363
user1173363

Reputation:

00-00-1900 in Mask Take --1___ Because 0 and 9 are the Masked text which refers, numeric.

0 - Digit, required. This element will accept any single digit between 0 and 9.

9 - Digit or space, optional.

You Just Right Click The Masked Text Box, And Go to Property. Click and Change Mask to 00-00-1\900.

You will get what you want.

1900 to 1999 in 1900.

Upvotes: 1

Kris Dunning
Kris Dunning

Reputation: 127

Take a look at this, see the remarks section. Sadly, it doesn't state whether you can make the 19 aspect of the last four digits fixed - you may need to write your own checks to enforce this.

Upvotes: 0

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