CODEWITHSUNDEEP
cloops
Cooldog117
Cooldog117

Reputation: 85

how to detect if a number is between two other numbers in C?

how do I detect if a user input int is between 2 numbers?

I've tried doing this:

int x=3;
printf("Enter the size of the triangle: ");
scanf("%d", &size);
odd=size%2;

for(x=3;x<21;x++)
{
  if(x==size&&odd==1)
  {
     break;
  }
  else
  {
 printf("The size must be an odd number and be between\n3 and 21, inclusive, please try again\n\n");
     printf("Enter the size of the triangle: ");
     scanf("%d",&size);
     odd=size%2;
     x=3;
  } 
}

But the only input I can use is 3.

Upvotes: 0

Views: 438

Answers (4)

paxdiablo
paxdiablo

Reputation: 881553

If your need is to continuously ask the user for a number until they enter one that's:

  • odd; and
  • between 3 and 21 inclusive,

you can use something like:

printf ("Enter the size of the triangle: ");
scanf ("%d", &size);
while ((x < 3) || (x > 21) || (x % 2 == 0)) {
    printf ("The size must be an odd number and be between\n"
        "3 and 21, inclusive, please try again.\n\n");
    printf ("Enter the size of the triangle: ");
    scanf ("%d", &size);
}

This is probably the simplest form. It gets the number then enters the while loop until it's valid.

You could refactor the printf/scanf pair into a separate function but that's probably not so important in a small snippet like this.

Upvotes: 1

millimoose
millimoose

Reputation: 39950

You already have all the bits of the solution in the code: 

if (size >= 3 && size <= 21) {
   // size is between 3 and 21 inclusive
} else {
   // size is less than 3 or more than 21
}

If you also want to ensure it's odd, you can add the condition:

if ((size >= 3) && (size <= 21) && (size % 2 == 1)) {
   // size is between 3 and 21 inclusive, and odd
} else {
   // size is less than 3 or more than 21 or even
}

Upvotes: 3

ohmu
ohmu

Reputation: 19760

printf("Enter the size of the triangle");
scanf("%d", &size);

if (3 <= size && size <= 21 && size % 2) {
    // size is between 3 and 21 (inclusive) and odd
}

Upvotes: 0

Andrejs Cainikovs
Andrejs Cainikovs

Reputation: 28454

How about:

if(x >= 3 && x <= 21 && x%2) {
    ...
}

Upvotes: 0

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