Reputation: 30445
How can I generate all of the 6 combinations of 2 treatments (A,B) in blocks of 4, such that in each block there is an equal number of A's and B's, using R?
"AABB","ABAB","ABBA","BBAA","BABA","BAAB"
P.S. The number of combinations is calculated as follows:
If
T = #treatments
n = #treatments in each block = k*T,
The number of combinations equals n! / [k!*k! (T times)]
Thank you
Upvotes: 3
Views: 1218
Reputation: 5696
The expected solution can also be achieved using the new iterpc
package.
I <- iterpc(c(2, 2), labels=c("A", "B"), ordered=TRUE)
getall(I)
# [,1] [,2] [,3] [,4]
# [1,] "A" "A" "B" "B"
# [2,] "A" "B" "A" "B"
# [3,] "A" "B" "B" "A"
# [4,] "B" "A" "A" "B"
# [5,] "B" "A" "B" "A"
# [6,] "B" "B" "A" "A"
Upvotes: 1
Reputation: 162311
The multicool
package implements an algorithm for permuting multisets --- exactly the task you want to have performed. Here's an example of what it can do:
library(multicool)
# Create a simple convenience function
enumAllPartitions <- function(multiset) {
m1 <- initMC(multiset) # Initialize the permutation object
N <- fact(length(multiset))/ # Calculate number of permutations
prod(fact(table(multiset)))
sapply(seq_len(N), function(X) paste(nextPerm(m1), collapse=""))
}
# Try it out with a few different multisets
x <- c("A", "A", "B", "B")
y <- c("G", "L", "L", "L")
z <- c("X", "X", "Y", "Z", "Z")
lapply(list(x,y,z), enumAllPartitions)
[[1]]
[1] "BBAA" "ABBA" "BABA" "ABAB" "AABB" "BAAB"
[[2]]
[1] "LLLG" "GLLL" "LGLL" "LLGL"
[[3]]
[1] "ZZYXX" "XZZYX" "ZXZYX" "ZZXYX" "XZZXY" "ZXZXY" "XZXZY" "XXZZY" "ZXXZY"
[10] "ZZXXY" "YZZXX" "ZYZXX" "XZYZX" "ZXYZX" "YZXZX" "XYZZX" "YXZZX" "ZYXZX"
[19] "XZYXZ" "ZXYXZ" "XZXYZ" "XXZYZ" "ZXXYZ" "YZXXZ" "XYZXZ" "YXZXZ" "XYXZZ"
[28] "XXYZZ" "YXXZZ" "ZYXXZ"
Upvotes: 1
Reputation: 57210
Something like this should work:
library(gtools)
t <- c('A','B')
k <- 2
n <- k * length(t)
t2 <- rep(t, k)
m <- permutations(n,n)
res <- unique(apply(m,MARGIN=1,function(x) paste(t2[x],collapse='')))
--------------------------------------------------------------------
res
[1] "ABAB" "ABBA" "AABB" "BAAB" "BABA" "BBAA"
Upvotes: 4