CODEWITHSUNDEEP
pythondjango
Kevin
Kevin

Reputation: 1133

Django url regex parameter capturing

I want to route the following uri to a view;

localhost:8000/?tag=Python

to

def index_tag_query(request, tag=None):

in my url conf, I've tried the following regex patterns but none seem to be capturing the request even though the regex looks good;

url(r'^\?tag=(?P<tag>\w+)/$', 'links.views.index_tag_query'),

url(r'^\/?\?tag=(?P<tag>\w+)/$', 'links.views.index_tag_query'),

url(r'^\/?\?tag=(?P<tag>.*)/$', 'links.views.index_tag_query'),

What gives?

Upvotes: 5

Views: 10156

Answers (1)

Timmy O&#39;Mahony
Timmy O&#39;Mahony

Reputation: 53971

You can't parse GET parameters from your URLconf. For a better explanation then I can give, check out this question (2nd answer): Capturing url parameters in request.GET

Basically, the urlconf parses and routes the URL to a view, passing any GET parameters to the view. You deal with these GET parameters in the view itself

urls.py

url(r^somepath/$', 'links.views.index_tag_query')

views.py

def index_tag_query(request):
    tag = request.GET.get('tag', None)
    if tag == "Python":
         ...

Upvotes: 8

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