Reputation: 2733
I have two classes, class A
and class B
.
A.h -> A.cpp
B.h -> B.cpp
And then, I set B as a member in class A. Then, class A can access class B by
#include <B.h>
But, how can I get the pointer of class A in class B and access the public member of class A?
I found some information about on the internet: a Cross-class. They said you can make it by setting the class B as a nested class in class A.
Do you have any other advice?
sorry. myCode: as follow..
class A:
#ifndef A
#define A
#include "B.h"
class A
{
public:
A() {
b = new B(this);
}
private:
B* b;
};
#endif
#ifndef B
#define B
#include"A.h"
class B
{
public:
B(A* parent = 0) {
this->parent = parent;
}
private:
A* parent;
};
#endif
Upvotes: 0
Views: 2978
Reputation: 5225
Just use forward declaration. Like:
A.h:
#ifndef A_h
#define A_h
class B; // B forward-declaration
class A // A definition
{
public:
B * pb; // legal, we don't need B's definition to declare a pointer to B
B b; // illegal! B is an incomplete type here
void method();
};
#endif
B.h:
#ifndef B_h
#define B_h
#include "A.h" // including definition of A
class B // definition of B
{
public:
A * pa; // legal, pointer is always a pointer
A a; // legal too, since we've included A's *definition* already
void method();
};
#endif
A.cpp
#inlude "A.h"
#incude "B.h"
A::method()
{
pb->method(); // we've included the definition of B already,
// and now we can access its members via the pointer.
}
B.cpp
#inlude "A.h"
#incude "B.h"
B::method()
{
pa->method(); // we've included the definition of A already
a.method(); // ...or like this, if we want B to own an instance of A,
// rather than just refer to it by a pointer.
}
Knowing that B is a class
is enough for compiler to define pointer to B
, whatever B
is. Of course, both .cpp
files should include A.h
and B.h
to be able to access class members.
Upvotes: 7