CODEWITHSUNDEEP
phpmodel-view-controllersymfonyroutes
Mathew
Mathew

Reputation: 8279

How to forward a request using a URL string in Symfony2

I want to perform a sub-request, but don't have the route in the format $this->forward() expects - I only have the url as a string.

// Symfony2 wants...
$this->forward('ProjectCustomerBundle:Customer:view', array('id' => 1234));

// I want... 
$this->forward('customer/view/1234');

Surely I can manually build a Route or Request object from the url to achieve this? I've got a sneaky suspicion that I'm missing something obvious here...

Upvotes: 3

Views: 2635

Answers (2)

Cosmologist
Cosmologist

Reputation: 508

https://github.com/Cosmologist/SymfonyCommonBundle#routing-utils

return $this->httpKernel->handle(Request::create($uri), HttpKernelInterface::SUB_REQUEST);

Upvotes: 0

grzechoo
grzechoo

Reputation: 1093

Use $this->get('router')->match('customer/view/1234') and you should get an array with _controller value and all other route parameters you need to pass.

Upvotes: 4

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