CODEWITHSUNDEEP
java
user1174834
user1174834

Reputation: 249

Parse input from string containing ints

I am trying to get input from a string containing ints. So when a user types in the command "getrange(1,12)" I need to read the inital command as a string, and the two numbers inside it as an ints. I was thinking I could do a number of Splits() but I think that might get messy. In addition Split() keeps them as strings I think.

My ultimate goal is to write an IF statement like this: 

if("getrange")
{

    while(1 <= 12)
    {
        output.println(MyArray[1])
        1++
    }
}

Any Ideas? I know this is pretty crude, let me know if I need to clarify. Thanks

Upvotes: 1

Views: 134

Answers (3)

Bhesh Gurung
Bhesh Gurung

Reputation: 51030

String input = "getrange(1,12)";
String[] parts = input.split("\\(");
System.out.println("Command: " + parts[0]);
String[] argsParts = parts[1].substring(0, parts[1].indexOf(")")).split(",");
int arg1 = Integer.parseInt(argsParts[0].trim());
int arg2 = Integer.parseInt(argsParts[1].trim());        
System.out.println("Args: " + arg1 + ", " + arg2);

Output:

Command: getrange
Args: 1, 12

Upvotes: 2

RussS
RussS

Reputation: 16576

 Scanner s = new Scanner(input);
 s.findInLine("getRange\((\\d+),(\\d+)\)");
 MatchResult result = s.match();
 //You should do some error checking here (are there enough matches ...)
 int StartRange == Integer.parseInt(result.group(0));
 int EndRange == Integer.parseInt(result.group(1));

And you can take it from there :)

Upvotes: 2

nolt2232
nolt2232

Reputation: 2644

Use a regular expression to get the numbers and then then do an Integer.parseInt() on the two pieces. The other option which is less ideal would be to do a combo of substring and split to remove the unwanted characters.

Upvotes: 1

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