CODEWITHSUNDEEP
php
DiegoP.
DiegoP.

Reputation: 45757

PHP calculate hours

I have two variables, example:

$from = 13:43:13;

$to = 18:53:13;

I need to calculate in PHP the hours between $from and $to, so that $total will be like:

$total = 5.10 // 5 hours and ten minutes

or

$total = 0.40 // 0 hours and 40 minutes

I do not mind seconds, what I need is hours and minutes.

Please help me :)

Upvotes: 3

Views: 15579

Answers (4)

Chris Campbell
Chris Campbell

Reputation: 1

There's a flaw in the calculation. The result shows 5.2 when it should be 5.02.
Try using 09:58 as the start time and 15:00 as the end time.

Upvotes: 0

FtDRbwLXw6
FtDRbwLXw6

Reputation: 28929

I like using the object-oriented approach, using the DateTime class:

$from = new DateTime('13:43:13');
$to = new DateTime('18:53:13');

echo $from->diff($to)->format('%h.%i'); // 5.10

Upvotes: 4

Paul Norman
Paul Norman

Reputation: 1693

$from       = '13:43:13';
$to         = '18:53:13';

$total      = strtotime($to) - strtotime($from);
$hours      = floor($total / 60 / 60);
$minutes    = round(($total - ($hours * 60 * 60)) / 60);

echo $hours.'.'.$minutes;

Upvotes: 5

Amit Yadav
Amit Yadav

Reputation: 1861

How about making about a function and putting the below code into that?

<?php
    $from = $_REQUEST['start_time']; 
    $to = $_REQUEST['end_time']; 
    $action = $_REQUEST['action']; 
?> 

<? 
    if($action && ($action == "go")){ 
        list($hours, $minutes) = split(':', $from); 
        $startTimestamp = mktime($hours, $minutes); 

        list($hours, $minutes) = split(':', $to); 
        $endTimestamp = mktime($hours, $minutes); 

        $seconds = $endTimestamp - $startTimestamp; 
        $minutes = ($seconds / 60) % 60; 
        $hours = round($seconds / (60 * 60)); 

        echo "Time passed: <b>$hours</b> hours and <b>$minutes</b> minutes"; 
    } 
?>

Please add the fields to receive the values...

Upvotes: 0

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