Reputation: 3287
What is the best way to concatenate two integers to an integer in Fortran?
integer a = 999
integer b = 1111
integer c
should be 9991111
Thanks, SM.
Upvotes: 3
Views: 6195
Reputation: 6241
Here is an example code that does what you need. It writes integers into character strings, trims and concatenetes them, and then reads the result integer from concatenated character string:
integer :: a,b,c
character(len=99) :: char_a,char_b,char_c
a = 999
b = 1111
write(unit=char_a,fmt=*)a
write(unit=char_b,fmt=*)b
char_c = trim(adjustl(char_a))//trim(adjustl(char_b))
read(unit=char_c,fmt=*)c
print*,c
end
Edit: Note that this example is general for any integer lengths, assuming they fit into their respective kind
(no integer overflow).
Upvotes: 8
Reputation: 6878
You can use the information of the order of the number:
integer :: a = 999
integer :: b = 1111
integer :: c
c = a * 10**(ceiling(log10(real(b)))) + b
write(*,*) c
Upvotes: 3
Reputation: 46316
Your best bet is to use internal files to convert your two integers to a character, and then convert this back to an integer.
There is no intrinsic procedure for converting a numeric value to a character/string representation. See this discusson on Fortran Wiki for more information (see the part headed "Note").
As an example, in your case you could use the following:
program test_conversion
implicit none
integer :: a=999
integer :: b=1111
integer :: c
character(len=7) :: temp
write(temp, '(i3.3, i4.4)') a, b ! You may need to change these format specifiers
read(temp, *) c
print*, c ! This prints 9991111
end program test_conversion
You will have to change the format string if you want different widths of the character representation of your integers.
Upvotes: 0