CODEWITHSUNDEEP
java
Zack Macomber
Zack Macomber

Reputation: 6905

Java Short addition questions

This may have already been answered in another post, but I just am not getting why something won't compile in my test Java app (1.7.0_01).

This compiles:

Short a = (short)17;
a = (short)2 + 1;

I know that "a + a" will result in an integer. This compiles fine:

Short a = (short)17;
int shortTest = a + a;

So why doesn't this compile?

Short a = (short)17;
a = (short)a + a;

Also, am I right to assume you can't use +=, -=, etc... on Shorts because of the conversion to integer? If it's possible to do those operations, can someone provide an example?

Edit 1
There's been some votes to close this post as it's been suggested that it's a duplicate of Primitive type 'short' - casting in Java. However, my example revolves around the Wrapper "Short" object. There are important and more complicated rules around casting Wrapper objects and that's what I think needs to be focussed on.

Also, as my original post indicates, I'm looking for the "why" behind the 3rd code block. I'm also interested to know if it's possible to use "+=", "-=", etc... on the Short Wrapper.

Upvotes: 14

Views: 19560

Answers (1)

Dmitri
Dmitri

Reputation: 9157

Seems the correct answer was removed for some reason: (short) a + a is equivalent to ((short) a) + a, you're looking for (short)(a + a).

Edit

The 'why' behind it is operator precedence, same reason why 1 + 2 * 3 is 7 and not 9. And yes, primitives and literals are treated the same.

You can't do Short s = 1; s += 1; because it's the same as a = a + 1; where a is converted to an int and an int can't be cast to a Short. You can fix the long version like so: a = (short) (a + 1);, but there's no way to get the explicit cast in there with +=.

It's pretty annoying.

Upvotes: 13

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