CODEWITHSUNDEEP
phpdynamicsession
user2190919
user2190919

Reputation:

PHP: Load content dynamically based on the link clicked on the previous page?

I've been Google-ing this for the past 24 hours, pretty much. I can't seem to find an answer that fits my scenario, even though I know it's widely used.

I have many links on one page (let's call it "page 1") of my website and I would like to them all to head to one, blank page (and this "page 2") and then have the content dynamically load, depending on what link was clicked on the previous page.

All I know is that I need to be able to set a PHP variable with the hyperlinks on page 1 and use some kind of if(isset($_SESSION['phpVariable'])){ include('path/content.fileExt')} on page 2 page so that it's ready to receive the variable and load the content accordingly.

I just have no clue how to do this, as I only started learning PHP yesterday. Help? :( :L

Upvotes: 3

Views: 5349

Answers (3)

Fad
Fad

Reputation: 9858

You can pass an identifier of the content to be loaded through the URL.

Ex: Set a value for one of the GET parameter to be the identifier for the content of page 2

<a href="page2.php?pageid=content">Link to Page 2</a>

And then in page 2 just check for the value and load the content accordingly.

include_once 'content/' . $_GET['pageid'];

Upvotes: 1

CoffeeRain
CoffeeRain

Reputation: 4522

You could use the $_GET[] variable. On page1, the links could be to page2?food=bacon or page2?food=foo. On page2, you could say...

if ($_GET['food']=='bacon')
{
  // Stuff here that prints what you want.
}
elsif ($_GET['food']=='foo')
{
  // Stuff here that prints what you want.
}

Upvotes: 2

Mark Price
Mark Price

Reputation: 590

http://www.w3schools.com/php/php_get.asp

www.example.com/index.php?page=something_here

$_get["page"]

Would return "something_here"

Upvotes: 0

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