CODEWITHSUNDEEP
c++windows
Valmond
Valmond

Reputation: 2969

How can you open a file with the program associated with its file extension?

Is there a simple way to open a file by its associated program in windows? (like double clicking it in windows explorer but done automatically with my code)

For example, on computer A, "text.txt" will be opened in wordpad but on computer B it will be opened by Notepad++ because of the users file extension assignments.

I tried ShellExecute

ShellExecute(0, L"open", L"c:\\windows\\notepad.exe" ,L"c:\\outfile.txt" , 0 , SW_SHOW );

which works but if I omit the notepad.exe parameter weird things happen (a random explorer is shown).

Upvotes: 23

Views: 34043

Answers (6)

Alex K.
Alex K.

Reputation: 175766

If lpFile specifies a document file, the flag is simply passed to the associated application

So you need to substitute "c:\\windows\\notepad.exe" with the actual file you want to open and leave lpParameters null.

Upvotes: 1

Blacktempel
Blacktempel

Reputation: 3995

A little more possibilities here:

If you want to open - for example - the file by default with Notepad++ (if installed), you could scan for it's registry key if it exists and where it is, (Usually HKLM\SOFTWARE\Wow6432Node\Notepad++ [tested Win7]) then take that path and open it.

std::wstring file = L"C:\\Outfile.txt";

if (NotepadPlusPlusExists()) //Open with Notepad++ or use an other program... (maybe your own ?)
{
    std::wstring wsNPPPath = GetNotepadPlusPlusPath();
    ShellExecuteW(HWND, L"open", wsNPPPath.c_str(), file.c_str(), NULL, SW_NORMAL);
}
else //Open with default associated program <---
    ShellExecuteW(HWND, NULL, file.c_str(), NULL, NULL, SW_NORMAL);

If you want the user to be able to change the default program or select a program he/she wants to use, you may open the "Open with" dialog.

//std::wstring StringArgsW(const wchar_t *format, ...);
std::wstring wsCmdOpenWith = StringArgsW(L"C:\\Windows\\system32\\shell32.dll,OpenAs_RunDLL \"%s\"", file.c_str());
ShellExecuteW(HWND, L"open", L"C:\\Windows\\system32\\rundll32.exe", wsCmdOpenWith.c_str(), NULL, SW_NORMAL);

You can also open the file in explorer.

std::wstring wsCmdExplorer = StringArgsW(L"/select,\"%s\"", file.c_str());
ShellExecuteW(HWND, L"open", L"explorer.exe", wsCmdExplorer.c_str(), NULL, SW_NORMAL);

Upvotes: 4

Mark Ransom
Mark Ransom

Reputation: 308140

You want to use the file to open as the file argument, not the parameter argument. No need to specify which program to use, ShellExecute will look it up for you.

ShellExecute(0, 0, L"c:\\outfile.txt", 0, 0 , SW_SHOW );

By leaving the verb as NULL (0) rather than L"open", you get the true default action for the file type - usually this is open but not always.

Upvotes: 36

Frank Schmitt
Frank Schmitt

Reputation: 30775

According to the MS Knowledge Base, ShellExecute should work (we do this in Delphi all the time):

ShellExecute(Handle, "Open", Filename, "", "C:\", SW_SHOWNORMAL)

Upvotes: 2

Sebastian Mach
Sebastian Mach

Reputation: 39089

See Launching Applications:

ShellExecute(NULL, "open", L"c:\\outfile.txt", NULL, NULL, SW_SHOW);

On windows, a good memory hook is to think of all data-files being executable by the shell. You can also try it out in a command box, where you can just type a filename, and it will be opened up. Or, the other way around, every file in Windows can be opened, and the default opening-action for executable files is to execute them.

Upvotes: 7

mcnicholls
mcnicholls

Reputation: 846

Maybe try start instead of open?

Upvotes: 0

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