CODEWITHSUNDEEP
c++linuxterminal
Roronoa Zoro
Roronoa Zoro

Reputation: 1013

What does 'directed to standard output (cout)' means?

I just downloaded this code in which it says in the manual that the 'main results are directed to standard output (cout)'. However, when I run the code as described in the manual, everything runs just fine but I don't see any results showing on the terminal (not being written to an output file either)

This is a Linux code so I tried to run it form both Ubuntu terminal and from cygwin but I'm having the same problem - nothing is showing.

Could it be that 'the main results are directed to a standard output (cout)' means anything else? Other that it's supposed to show the results on the terminal?

Upvotes: 0

Views: 159

Answers (3)

Shantanu
Shantanu

Reputation: 383

Ensure that there is no "wrapper" script encapsulating the program, which is internally redirecting the standard output to a file.

Upvotes: 0

paxdiablo
paxdiablo

Reputation: 881273

Unless you have the source code, it's a little difficult for you (or us) to tell if it may have another meaning ("directed to standard output (cout)" is a little hard to misinterpret however, there's no other sane reading of that snippet).

If you do have the source, you can look for the cout <<-type statements to ensure something is done. You may have to examine the logic closely to see why nothing is being output for your specific case.

If you can share the source with us, we could help out further but it doesn't appear you're comfortable with that so the "analyse the code yourself" is probably the best answer you'll get.

Of course, there's always the option of going back to the author if your analysis is not going well, or if you don't have the source.

Upvotes: 1

Tim
Tim

Reputation: 60110

There's no other meaning that I can think of for "standard output (cout)" - it should be the terminal that's running the program. Are you sure the program produces output?

Upvotes: 3

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