Oliver
Oliver

Reputation: 11617

Setting two scalar variables in one SELECT statement?

I want to do this:

Declare @a int;
Declare @b int;

SET @a,@b = (SELECT StartNum,EndNum FROM Users Where UserId = '1223')

PRINT @a
PRINT @b

But this is invalid syntax. How do I set multiple scalar variables in one select statement? I can do:

Declare @a int;
Declare @b int;

SET @a = (SELECT StartNum FROM Users Where UserId = '1223')
SET @b = (SELECT EndNum FROM Users Where UserId = '1223')

PRINT @a
PRINT @b

But this will take twice as long. What is the fastest way?

Upvotes: 58

Views: 79177

Answers (3)

juergen d
juergen d

Reputation: 204924

DECLARE @a int;
DECLARE @b int;

SELECT @a = StartNum, @b = EndNum 
FROM Users 
WHERE UserId = '1223'

Upvotes: 136

rvazquezglez
rvazquezglez

Reputation: 2454

If you are doing this in a stored procedure and don't want the result of the select in an output resultset you will need to use the word INTO.

Declare @a int;
Declare @b int;

SELECT StartNum, EndNum 
FROM Users 
Where UserId = '1223'
INTO @a, @b;

It also can be used like this:

SELECT StartNum, EndNum 
INTO @a, @b
FROM Users 
Where UserId = '1223';

Upvotes: 7

aF.
aF.

Reputation: 66757

Do it like this:

Declare @a int;
Declare @b int;

SELECT @a=StartNum,@b=EndNum FROM Users Where UserId = '1223'

PRINT @a
PRINT @b

Upvotes: 15

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