CODEWITHSUNDEEP
pythonparsing
user1130601
user1130601

Reputation: 237

Python - Correct Method of Parsing

I'm currently working on a script that'll be working with Youtubes API. I'm still learning how to correctly parse using Python, but am a little lost on what method to take for something like this.

I have this string:

[{'term': u'Video Blogging', 'scheme': None, 'label': None}, {'term': u'blogging', 'scheme': None, 'label': None}, {'term': u'stuff', 'scheme': None, 'label': None}, {'term': u'Videos', 'scheme': None, 'label': None}]

I need to take that, and turn it in to this:

Video Blogging, blogging, stuff, Videos

What would be the best approach to solve this? Any help is appreciated, thanks!

Upvotes: 0

Views: 89

Answers (3)

Joel Cornett
Joel Cornett

Reputation: 24788

For this specific case, you can use a list comprehension:

    list_of_stuff = [
            {'term': u'Video Blogging', 'scheme': None, 'label': None}, 
            {'term': u'blogging', 'scheme': None, 'label': None}, 
            {'term': u'stuff', 'scheme': None, 'label': None}, 
            {'term': u'Videos', 'scheme': None, 'label': None}
            ]     

    parsed_string = ', '.join([d['term'] for d in list_of_stuff])

Upvotes: 0

dorsh
dorsh

Reputation: 24670

>>> l = [{'term': u'Video Blogging', 'scheme': None, 'label': None}, {'term': u'blogging', 'scheme': None, 'label': None}, {'term': u'stuff', 'scheme': None, 'label': None}, {'term': u'Videos', 'scheme': None, 'label': None}]
>>> [a.get('term') for a in l]
[u'Video Blogging', u'blogging', u'stuff', u'Videos']

and if you want to get the items as a comma-delimited string, use:

>>> ', '.join(a.get('term') for a in l)
u'Video Blogging, blogging, stuff, Videos'

I used a.get('term') instead of a['term'] to avoid a KeyError for items without a term key.

Upvotes: 4

jcollado
jcollado

Reputation: 40374

It should be something like this:

>>> l = [{'term': u'Video Blogging', 'scheme': None, 'label': None}, {'term': u'blogging', 'scheme': None, 'label': None}, {'term': u'stuff', 'scheme': None, 'label': None}, {'term': u'Videos', 'scheme': None, 'label': None}]
>>> ', '.join([d['term'] for d in l])
u'Video Blogging, blogging, stuff, Videos'

Upvotes: 1

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