CODEWITHSUNDEEP
c++g++
ezpresso
ezpresso

Reputation: 8136

Initializing const member within class declaration in C++

In PHP and C# the constants can be initialized as they are declared:

class Calendar3
{
    const int value1 = 12;
    const double value2 = 0.001;
}

I have the following C++ declaration of a functor which is used with another class to compare two math vectors:

struct equal_vec
{
    bool operator() (const Vector3D& a, const Vector3D& b) const
    {
        Vector3D dist = b - a;
        return ( dist.length2() <= tolerance );
    }

    static const float tolerance = 0.001;
};

This code compiled without problems with g++. Now in C++0x mode (-std=c++0x) the g++ compiler outputs an error message:

error: ‘constexpr’ needed for in-class initialization of static data member ‘tolerance’ of non-integral type

I know I can define and initialize this static const member outside of the class definition. Also, a non-static constant data member can be initialized in the initializer list of a constructor.

But is there any way to initialize a constant within class declaration just like it is possible in PHP or C#?

Update

I used static keyword just because it was possible to initialize such constants within the class declaration in g++. I just need a way to initialize a constant in a class declaration no matter if it declared as static or not.

Upvotes: 97

Views: 110948

Answers (5)

nilesOien
nilesOien

Reputation: 49

I ran into real problems with this, because I need the same code to compile with differing versions of g++ (the GNU C++ compiler). So I had to use a macro to see which version of the compiler was being used, and then act accordingly, like so

#if __GNUC__ > 5
 #define GNU_CONST_STATIC_FLOAT_DECLARATION constexpr
#else
 #define GNU_CONST_STATIC_FLOAT_DECLARATION const
#endif

GNU_CONST_STATIC_FLOAT_DECLARATION static double yugeNum=5.0;

This will use 'const' for everything before g++ version 6.0.0 and then use 'constexpr' for g++ version 6.0.0 and above. That's a guess at the version where the change takes place, because frankly I didn't notice this until g++ version 6.2.1. To do it right you may have to look at the minor version and patch number of g++, so see

https://gcc.gnu.org/onlinedocs/cpp/Common-Predefined-Macros.html

for the details on the available macros.

With gnu, you could also stick with using 'const' everywhere and then compile with the -fpermissive flag, but that gives warnings and I like my stuff to compile cleanly.

Not great, because it's specific to gnu compilers, butI suspect you could do similar with other compilers.

Upvotes: 4

Open AI - Opting Out
Open AI - Opting Out

Reputation: 24163

If you only need it in the one method you can declare it locally static:

struct equal_vec
{
    bool operator() (const Vector3D& a, const Vector3D& b) const
    {
        static const float tolerance = 0.001f;
        Vector3D dist = b - a;
        return ( dist.length2() <= tolerance );
    }
};

Upvotes: 2

Anthony Williams
Anthony Williams

Reputation: 68691

In C++11, non-static data members, static constexpr data members, and static const data members of integral or enumeration type may be initialized in the class declaration. e.g.

struct X {
    int i=5;
    const float f=3.12f;
    static const int j=42;
    static constexpr float g=9.5f;
};

In this case, the i member of all instances of class X is initialized to 5 by the compiler-generated constructor, and the f member is initialized to 3.12. The static const data member j is initialized to 42, and the static constexpr data member g is initialized to 9.5.

Since float and double are not of integral or enumeration type, such members must either be constexpr, or non-static in order for the initializer in the class definition to be permitted.

Prior to C++11, only static const data members of integral or enumeration type could have initializers in the class definition.

Upvotes: 164

znkr
znkr

Reputation: 1756

Initializing static member variables other than const int types is not standard C++ prior C++11. The gcc compiler will not warn you about this (and produce useful code nonetheless) unless you specify the -pedantic option. You then should get an error similiar to:

const.cpp:3:36: error: floating-point literal cannot appear in a constant-expression
const.cpp:3:36: warning: ISO C++ forbids initialization of member constant ‘tolerance’ of non-integral type ‘const float’ [-pedantic]

The reason for this is that the C++ standard does not specifiy how floating point should be implemented and is left to the processor. To get around this and other limitations constexpr was introduced.

Upvotes: 50

StilesCrisis
StilesCrisis

Reputation: 16310

Yes. Just add the constexpr keyword as the error says.

Upvotes: 15

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