Reputation: 24768
Can you explain why
This one gives $? = 1
echo "uus" | grep -w -o [0123456789]\*
and this one give $? = 0
echo "-uus" | grep -w -o [0123456789]\*
Upvotes: 1
Views: 314
Reputation: 212298
grep is matching the zero length word between '-' and 'u'.
Upvotes: 0
Reputation: 385710
Your regular expression can match an empty string. The -w
flag means that any match must be preceded by beginning-of-line or a non-word character, and followed by end-of-line or a non-word character.
In the case of uus
, the beginning of line is followed be a word character, so grep
can't match an empty string as a word there. The end of line is preceded by a word character, so grep
can't match an empty string as a word there.
In the case of -uus
, the beginning of line is followed by -
, which is a non-word character, so grep
can match the empty string as a word between the beginning of the line and the -
character.
Upvotes: 5