CODEWITHSUNDEEP
xmlxhtmlxpath
flybywire
flybywire

Reputation: 273452

How can I find the link URL by link text with XPath?

I have a well formed XHTML page. I want to find the destination URL of a link when I have the text that is linked.

Example

<a href="http://stackoverflow.com">programming questions site</a>
<a href="http://cnn.com">news</a>

I want an XPath expression such that if given programming questions site it will give http://stackoverflow.com and if I give it news it will give http://cnn.com.

Upvotes: 97

Views: 177623

Answers (6)

Brian Agnew
Brian Agnew

Reputation: 272237

//a[text()='programming quesions site']/@href

which basically identifies an anchor node <a> that has the text you want, and extracts the href attribute.

Upvotes: 10

Abdo
Abdo

Reputation: 14051

For case insensitive contains, use the following:

//a[contains(translate(text(),'PROGRAMMING','programming'), 'programming')]/@href

translate converts capital letters in PROGRAMMING to lower case programming.

Upvotes: 4

MaDeuce
MaDeuce

Reputation: 829

Too late for you, but for anyone else with the same question...

//a[contains(text(), 'programming')]/@href

Of course, 'programming' can be any text fragment.

Upvotes: 80

Badaro
Badaro

Reputation: 3480

Should be something similar to:

//a[text()='text_i_want_to_find']/@href

Upvotes: 156

Miguel Vaz
Miguel Vaz

Reputation: 11

if you are using html agility pack use getattributeValue:

$doc2.DocumentNode.SelectNodes("//div[@class='className']/div[@class='InternalClass']/a[@class='InternalClass']").GetAttributeValue("href","")

Upvotes: 1

Baxter Tidwell
Baxter Tidwell

Reputation: 381

Think of the phrase in the square brackets as a WHERE clause in SQL.

So this query says, "select the "href" attribute (@) of an "a" tag that appears anywhere (//), but only where (the bracketed phrase) the textual contents of the "a" tag is equal to 'programming questions site'".

Upvotes: 6

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