CODEWITHSUNDEEP
javascriptregex
Anicho
Anicho

Reputation: 2667

Regex get all text from # to quotation

Okay so I currently have:

/(#([\"]))/g;

I want to be able to check for a string like:

#23ad23"

Whats wrong with my regex?

Upvotes: 0

Views: 98

Answers (3)

mmdemirbas
mmdemirbas

Reputation: 9158

For minimum match count (bigger-length matches): #(.+)\"

For maximum match count (smaller-length matches): #(.+?)\"

Upvotes: 1

Billy Moon
Billy Moon

Reputation: 58531

Your regex (/(#([\"]))/g) breaks down like this:

without start/end delimiters/flags and capturing braces..

#[\"]

which just means #, followed by ", but the square brackets for the class are unnecessary, as there is only one item, so equivalent to...

#"

I think you want to match all characters between # and " inclusive (and captured exclusively).

Start with regex like this:

#.+?"

Which means # followed by anything (.) one or more times (+) un-greedily (?) followed by "

so with the capturing brackets, and delimeters...

/(#(.+?)")/g

Upvotes: 2

David Hellsing
David Hellsing

Reputation: 108500

Is this how you mean?

/(#([^\"]+))/g;

This will include everything until it reaches the " char.

Upvotes: 1

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