CODEWITHSUNDEEP
regexbashshellgrep
Jonathan Frampton
Jonathan Frampton

Reputation: 33

Regex in grep -E not working as expected

I'm working on a bash shell script, which goes through a folder and eventually makes new directories based off file names. Now I want to go through each file and strip away unwanted slashes of the path and ignore the fileextension before making a new directory. To test this, I'm echoing my file like this:

#!/bin/sh

cpath=`pwd`
for file in $cpath/*;do
echo $file | grep -E '(?!.*/).+(?=\.)'
done

But grep filters out everything and I get no output. I worked out the regex with RegExr http://gskinner.com/RegExr/?2vu6b
Negative lookahead to match the last slash and positive lookahead matching the last dot.

Upvotes: 3

Views: 516

Answers (1)

jaypal singh
jaypal singh

Reputation: 77105

I am not sure if Negative lookahead is a part of Extended RE. But you can do something like this -

#!/bin/bash

for file in $PWD/*; do
basename "${file%.*}"
done

Upvotes: 2

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