Reputation: 17374
I solved this problem in another instance by making some workaround but I want to get it clear this time as I understand my problem better.
My asp.net net page has a search functionality that searches the database based on 5 fields. The result is displayed in the gridview. The gridview is editable and I can update values. The problem is if I want to update multiple values, gridview won't allow it. So I included an extra column for checkbox. I have added a footer which has link to update all checked records.
Ok so here is the problem? How do I send the whole gridview to another page where I can capture the gridview values?
By default the page is submitted onto itself. If I change the default action page, the whole gridview and search, nothing will work.
So how do I submit the whole page (or part of it) to a different page other than the default action script?
Upvotes: 1
Views: 107
Reputation: 111
I have not tried this specifically with a gridview, but I think a Cross Page PostBack should work. I have a search feature on my website as well and this is what I use.
Set the PostBackUrl of the Button that is causing the PostBack to the Destination page. Let’s assume your source page is search.aspx and your destination page is SearchResult.aspx
Inside search.aspx:
<asp:Button ID="btnSearch" runat="server" Text="Search" CssClass="right"
ValidationGroup = "Search"
PostBackUrl="~/SearchResult.aspx"
onclick="btnSearch_Click"/>
The form will be posted to SearchResult.aspx. Inside SearchResult.aspx, you add this directive:
<%@ PreviousPageType VirtualPath="~/Search.aspx" %>
And in the code behind, you can acess any control like this:
PreviousPage.<mycontrol>
Hope this help.
Upvotes: 1
Reputation: 17380
Have you tried using the Session
? Just add the DataSource
, or the Gridview
itself to the Session
and load it in the other Page and then Dispose()
it.
Good luck!
UPDATE:
I have accomplished this in the past through Cross-Page Posting. This is how I did it now for testing purposes:
Default.aspx:
<asp:Button ID="Button1" runat="server" Text="Button" onclick="Button1_Click" PostBackUrl="SearchResult.aspx" />
SearchResult.aspx.cs:
protected void Page_Init(object sender, EventArgs e)
{
if (PreviousPage != null)
{
if (Page.PreviousPage.FindControl("GridView1") != null)
{
GridView grid = (GridView)Page.PreviousPage.FindControl("GridView1");
grid.ID = "myGrid";
this.form1.Controls.Add(grid);
}
}
}
Hopefully this helps.
Upvotes: 1