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javascriptarraysjson
Dylan Cross
Dylan Cross

Reputation: 5986

Javascript array, with array inside?

I want to store an array of information, with a subset of information for each one. so I want something like:

var users = [{userID:1, userName:robert}, {userID:2, userName:daniel}]

then to retrieve the variable:

users.userID // 1, 2
users.userName // robert, daniel

or something, i want to be able to get the information associated with the userID.

Upvotes: 0

Views: 103

Answers (5)

Xavier John
Xavier John

Reputation: 9477

Here is one way to do it

        var array1 = new Array(1,2,3,4);
        var array2 = new Array(8,9,10,11,12,13);
        var array3 = new Array( array1, array2);
        console.log(array1);
        console.log(array2);
        console.log(array3);

Will give you the right results

Upvotes: 0

Robert Peters
Robert Peters

Reputation: 4104

Depending on your problem I would think about redoing the array along the line of the following

var users = { 'id1' : { 'userName' :'robert'},
              'id2': { 'userName ': 'daniel'}};

alert(users.id1.userName);
alert( eval('users.id' + 1 + '.userName'));

Upvotes: 1

caleb
caleb

Reputation: 1637

Yes, you can do that, in a variety of ways. Suppose you have:

var users = [{userID: 1, userName: robert}, {userID: 2, userName: daniel}];

To retrieve the userID and userName for Robert, you have access them via users[0].userID and users[0].userName.

If instead you want to retrieve them by users.userID[0] and users.userName[0], then you need to store it this way:

var users = {userID: [1, 2], userName: [robert, daniel]};

If you are asking how to transform the first form to the second, use this:

function transform(source) {
    var result = {};
    for (var i = 0; i < source.length; i++) {
        for (property in source[i]) {
            if (typeof result[property] == "undefined")
                result[property] = [];
            result[property].push(source[i][property]);
        }
    }
}

And use it this way:

var transformed_users = transform(users);

Do note that this transform function is specific to your data structure.

Upvotes: 0

akonsu
akonsu

Reputation: 29576

this generates an array of user IDs:

 [{userID:1, userName:robert},
        {userID:2, userName:daniel}].map(function (x) { return x.userID; });

Upvotes: 0

Mikey G
Mikey G

Reputation: 3491

This might help:

var desiredUserID = 2;

var userList = [ {userID: 1, userName: "robert"}, {userID:2, userName:"daniel"} ];

for(x=0;x<=userList.length;x++) {

    if(userList[x].userID == desiredUserID){

         alert(userList[x].userName);   

    }

}

Upvotes: 0

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