Reputation: 21
I have a html file with russian text. How i can get all words in text without html tags, special symbols, etc ?
Example:
<html>...<body>...<div id='text'>Foo bar! Foo, bar.</div></body></html>
I need:
['foo','bar','Foo','bar']
I tried nltk, but it does not support russian words.
Upvotes: 2
Views: 690
Reputation: 12891
Use regex to remove the tags. Nltk is all about language analysis (nouns vs verbs) and word meaning (semantics) not string removal and pattern matching although I can see how someoneaybe confused.
Here is a removal function using regex
import re
def remove_html_tags(data):
p = re.compile(r'<.*?>')
return p.sub('', data)
Upvotes: 0
Reputation: 1825
Use lxml
. It can strip tags, elements, and more:
import urllib2
from lxml import etree
URL = 'http://stackoverflow.com/questions/9230675/python-html-processing'
html = urllib2.urlopen(URL).read()
tree = etree.fromstring(html, parser=etree.HTMLParser())
tree.xpath('//script')
# [<Element script at 102f831b0>,
# ...
# <Element script at 102f83ba8>]
tree.xpath('//style')
# [<Element style at 102f83c58>]
tags_to_strip = ['script', 'style']
etree.strip_elements(tree, *tags_to_strip)
tree.xpath('//style')
# []
tree.xpath('//script')
# []
body = tree.xpath('//body')
body = body[0]
text = ' '.join(body.itertext())
tokens = text.split()
# [u'Stack',
# u'Exchange',
# u'log',
# u'in',
# ...
# u'Stack',
# u'Overflow',
# u'works',
# u'best',
# u'with',
# u'JavaScript',
# u'enabled']
In case of text in russian you get tokens looking likes this:
# [u'\xd1\x8d\xd1\x84\xd1\x84\xd0\xb5\xd0\xba\xd1\x82\xd1\x8b\xe2\x80\xa6',
# u'\xd0\x9c\xd0\xb0\xd1\x80\xd0\xba',
# ...
# u'\xd0\x9c\xd0\xb0\xd0\xb9\xd0\xb5\xd1\x80']
Errors handling is your home assignment.
Upvotes: 0
Reputation: 574
I'm using lxml library to parse xml/html. lxml works good with any unicode data.
Upvotes: 4