Reputation: 2077
This works but I'm not sure why. In function capIn()
, in my mind the line $botcap.slideDown("slow")
should slide the div down. It slides it up. If I try using .slideUp()
nothing happens as if it is trying to slide it down. Can anyone explain this to me?
$(".slide").hover(capIn, capOut);
function capIn(){
//slide top caption down
var $topcap = $(this).children(".topcap");
$topcap.slideDown("slow");
//slide bottom caption up
//!! Why does slideDown slide caption up here?
var $botcap = $(this).children(".botcap");
$botcap.slideDown("slow")
}
function capOut(){
//slide top back up
var $topcap = $(this).children(".topcap");
$topcap.slideUp("slow");
//slide bottom back down
var $botcap = $(this).children(".botcap");
$botcap.slideUp("slow");
}
Upvotes: 5
Views: 3890
Reputation: 11
This is because of positioning the element with absolute position and bottom: 0; This will actually treat the element as if it is bottom-based, therefore its slideDown() is going upwards. It can be fixed by using top: (height of element) instead of bottom: 0.
Upvotes: 0
Reputation: 3078
One possible fix would be to wrap $('.botcap')
elements with a container and align the container to the bottom.
Upvotes: 0
Reputation: 20721
jQuery's slideDown
and slideUp
functions are actually misnomers. As the documentation for slideUp
puts it:
Hide the matched elements with a sliding motion.
The hiding is achieved by modifying the height of the element; normally, this means that the lower edge of the element appears to slide up, hence the name. However, if the element is anchored at the bottom (e.g. by setting position: absolute
and bottom: 0
), the height modification will make the top edge appear to slide down.
Upvotes: 9