CODEWITHSUNDEEP
javaandroidjson
Andrew Butler
Andrew Butler

Reputation: 1060

How to parse this JSON string

I'm trying to parse this string into java, but I keep getting errors.

{"id":1,"jsonrpc":"2.0","result":{"limits":{"end":3,"start":0,"total":3},"sources":[{"file":"/media/storage/media/re Music/","label":"re Music"},{"file":"/media/storage/media/ra Music/","label":"ra Music"},{"file":"addons://sources/audio/","label":"Music Add-ons"}]}}

When I use this code ...

String temp = //json code returned from up above
JSONObject obj = new JSONObject(temp);
JSONArray array = obj.getJSONArray("sources");

I get an error saying org.json.JSONObject Value... and then displays what is in temp. Any help?

Upvotes: 0

Views: 979

Answers (3)

kosa
kosa

Reputation: 66637

Your json should have top level object, from there you need to get child objects. See this link for more detail.

Upvotes: 0

Gus
Gus

Reputation: 6871

The array named "sources" is several levels deep. You need to traverse down into the json.

Code formatters help with this stuff...

http://jsonformatter.curiousconcept.com/

{
   "id":1,
   "jsonrpc":"2.0",
   "result":{
      "limits":{
         "end":3,
         "start":0,
         "total":3
      },
      "sources":[
         {
            "file":"/media/storage/media/re Music/",
            "label":"re Music"
         },
         {
            "file":"/media/storage/media/ra Music/",
            "label":"ra Music"
         },
         {
            "file":"addons://sources/audio/",
            "label":"Music Add-ons"
         }
      ]
   }
}

Upvotes: 2

CaseyB
CaseyB

Reputation: 25058

It looks like the "sources" array is in the "result" object. So you would need to get that object and then get the array from that like this:

JSONObject obj = new JSONObject(temp);
JSONObject result = obj.getJSONObject("result");
JSONArray array = result.getJSONArray("sources");

Upvotes: 0

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