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highBandWidth
highBandWidth

Reputation: 17321

Concatenating two one-dimensional NumPy arrays

How do I concatenate two one-dimensional arrays in NumPy? I tried numpy.concatenate:

import numpy as np
a = np.array([1, 2, 3])
b = np.array([4, 5])
np.concatenate(a, b)

But I get an error:

TypeError: only length-1 arrays can be converted to Python scalars

Upvotes: 420

Views: 580538

Answers (7)

Muhammad Yasirroni
Muhammad Yasirroni

Reputation: 2137

Slightly different problem, that is if you want two 1D array with shape (n,) into (2,n), then you have the following options:

import numpy as np

np.r_[[a], [a]]
np.stack([a, a])
np.vstack([a, a])
np.concatenate([[a], [a]])
np.array([a, a])

The fastest way is to use plain numpy.array:

import numpy
import perfplot

perfplot.show(
    setup=lambda n: numpy.random.rand(n),
    kernels=[
        lambda a: numpy.r_[[a], [a]],
        lambda a: numpy.stack([a, a]),
        lambda a: numpy.vstack([a, a]),
        lambda a: numpy.concatenate([[a], [a]]),
        lambda a: numpy.array([a, a]),
    ],
    labels=["r_", "stack", "vstack", "concatenate", "array"],
    n_range=[2 ** k for k in range(19)],
    xlabel="len(a)",
)

enter image description here

Upvotes: 0

Semjon Mössinger
Semjon Mössinger

Reputation: 1890

An alternative ist to use the short form of "concatenate" which is either "r_[...]" or "c_[...]" as shown in the example code beneath (see Link for additional information):

%pylab
vector_a = r_[0.:10.] #short form of "arange"
vector_b = array([1,1,1,1])
vector_c = r_[vector_a,vector_b]
print vector_a
print vector_b
print vector_c, '\n\n'

a = ones((3,4))*4
print a, '\n'
c = array([1,1,1])
b = c_[a,c]
print b, '\n\n'

a = ones((4,3))*4
print a, '\n'
c = array([[1,1,1]])
b = r_[a,c]
print b

print type(vector_b)

Which results in:

[ 0.  1.  2.  3.  4.  5.  6.  7.  8.  9.]
[1 1 1 1]
[ 0.  1.  2.  3.  4.  5.  6.  7.  8.  9.  1.  1.  1.  1.] 


[[ 4.  4.  4.  4.]
 [ 4.  4.  4.  4.]
 [ 4.  4.  4.  4.]] 

[[ 4.  4.  4.  4.  1.]
 [ 4.  4.  4.  4.  1.]
 [ 4.  4.  4.  4.  1.]] 


[[ 4.  4.  4.]
 [ 4.  4.  4.]
 [ 4.  4.  4.]
 [ 4.  4.  4.]] 

[[ 4.  4.  4.]
 [ 4.  4.  4.]
 [ 4.  4.  4.]
 [ 4.  4.  4.]
 [ 1.  1.  1.]]

Upvotes: 15

Winston Ewert
Winston Ewert

Reputation: 45039

Use:

np.concatenate([a, b])

The arrays you want to concatenate need to be passed in as a sequence, not as separate arguments.

From the NumPy documentation:

numpy.concatenate((a1, a2, ...), axis=0)

Join a sequence of arrays together.

It was trying to interpret your b as the axis parameter, which is why it complained it couldn't convert it into a scalar.

Upvotes: 556

Nico Schlömer
Nico Schlömer

Reputation: 58721

There are several possibilities for concatenating 1D arrays, e.g.,

import numpy as np

np.r_[a, a]
np.stack([a, a]).reshape(-1)
np.hstack([a, a])
np.concatenate([a, a])

All those options are equally fast for large arrays; for small ones, concatenate has a slight edge:

enter image description here

The plot was created with perfplot:

import numpy
import perfplot

perfplot.show(
    setup=lambda n: numpy.random.rand(n),
    kernels=[
        lambda a: numpy.r_[a, a],
        lambda a: numpy.stack([a, a]).reshape(-1),
        lambda a: numpy.hstack([a, a]),
        lambda a: numpy.concatenate([a, a]),
    ],
    labels=["r_", "stack+reshape", "hstack", "concatenate"],
    n_range=[2 ** k for k in range(19)],
    xlabel="len(a)",
)

Upvotes: 87

Pe Dro
Pe Dro

Reputation: 3023

Some more facts from the numpy docs :

With syntax as numpy.concatenate((a1, a2, ...), axis=0, out=None)

axis = 0 for row-wise concatenation axis = 1 for column-wise concatenation 

>>> a = np.array([[1, 2], [3, 4]])
>>> b = np.array([[5, 6]])

# Appending below last row
>>> np.concatenate((a, b), axis=0)
array([[1, 2],
       [3, 4],
       [5, 6]])

# Appending after last column
>>> np.concatenate((a, b.T), axis=1)    # Notice the transpose
array([[1, 2, 5],
       [3, 4, 6]])

# Flattening the final array
>>> np.concatenate((a, b), axis=None)
array([1, 2, 3, 4, 5, 6])

I hope it helps !

Upvotes: 4

kmario23
kmario23

Reputation: 61305

Here are more approaches for doing this by using numpy.ravel(), numpy.array(), utilizing the fact that 1D arrays can be unpacked into plain elements:

# we'll utilize the concept of unpacking
In [15]: (*a, *b)
Out[15]: (1, 2, 3, 5, 6)

# using `numpy.ravel()`
In [14]: np.ravel((*a, *b))
Out[14]: array([1, 2, 3, 5, 6])

# wrap the unpacked elements in `numpy.array()`
In [16]: np.array((*a, *b))
Out[16]: array([1, 2, 3, 5, 6])

Upvotes: 2

Gabe
Gabe

Reputation: 86698

The first parameter to concatenate should itself be a sequence of arrays to concatenate: 

numpy.concatenate((a,b)) # Note the extra parentheses.

Upvotes: 41

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