CODEWITHSUNDEEP
ruby
Cyrus
Cyrus

Reputation: 3717

Ruby one line of code, interrupting a block

I'm trying to write one line of code to tell me if there is an element in an array that meets a set of criteria and then breaks on true.

For example

I have [1,2,3,4,5,6,7,8,9,10,11,12] and I want to find the first element that is divisible by 2 and 3. I want to write a one liner that will return true as soon as it hits 6 and not process the remaining elements in the array.

I can write a for each loop and break, but I feel like there should be a way to do that in one line of code.

Upvotes: 1

Views: 198

Answers (2)

Mladen Jablanović
Mladen Jablanović

Reputation: 44110

any?:

[1,2,3,4,5,6,7,8,9,10,11,12].any?{|e| e % 2 == 0 && e % 3 == 0}

or you can combine it with all? and have a great tutorial example:

[1,2,3,4,5,6,7,8,9,10,11,12].any?{|e| [2, 3].all?{|d| e % d == 0}}

And if you actually need the first matching element returned, use find:

[1,2,3,4,5,6,7,8,9,10,11,12].find{|e| [2,3].all?{|d| e % d == 0}}
# => 6

Upvotes: 5

Roland Mai
Roland Mai

Reputation: 31097

You should use: find

[1,2,3,4,5,6,7,8,9,10,11,12].find{|e| e % 2 == 0 && e % 3 == 0}

It will return 6, and it won't process the values after 6.

Upvotes: 4

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