CODEWITHSUNDEEP
pythonlistfor-loop
rptynan
rptynan

Reputation: 300

How to compare all items in a list with an integer without using for loop

I have a couple of lists which vary in length, and I would like to compare each of their items with an integer, and if any one of the items is above said integer, it breaks the for loop that it is in.

for list in listoflists:
    if {anyiteminlist} > 70:
        continue    #as in skip to next list

    {rest of code here}

Basically, I need to say: "If anything in this list is above 70, continue the loop with the next list"

Upvotes: 7

Views: 61562

Answers (6)

sleeplessnerd
sleeplessnerd

Reputation: 22791

You can shorten it to this :D

for good_list in filter(lambda x: max(x)<=70, listoflists):
   # do stuff

Upvotes: 1

DSM
DSM

Reputation: 353499

Well, I'd probably do it using the generator expression, but since no one else has suggested this yet, and it doesn't have an (explicit) nested loop:

>>> lol = [[1,2,3],[4,40],[10,20,30]]
>>> 
>>> for l in lol:
...     if max(l) > 30:
...         continue
...     print l
... 
[1, 2, 3]
[10, 20, 30]

Upvotes: 3

Praveen Gollakota
Praveen Gollakota

Reputation: 39000

Using the builtin any is the clearest way. Alternatively you can nest a for loop and break out of it (one of the few uses of for-else construct).

for lst in listoflists:
    for i in lst:
        if i > 70:
            break
    else:
        # rest of your code
        pass

Upvotes: 0

John La Rooy
John La Rooy

Reputation: 304463

Don't use list as a variable name, it shadows the builtin list(). There is a builtin function called any which is useful here

if any(x>70 for x in the_list):

The part inbetween the ( and ) is called a generator expression

Upvotes: 23

jterrace
jterrace

Reputation: 67163

You can use the built-in function any like this:

for list in listoflists:
    if any(x < 70 for x in list):
        continue

The any function does short-circuit evaluation, so it will return True as soon as an integer in the list is found that meets the condition.

Also, you should not use the variable list, since it is a built-in function.

Upvotes: 1

dlowe
dlowe

Reputation: 159

If you're using python 2.5 or greater, you can use the any() function with list comprehensions.

for list in listoflists:
  if any([i > 70 for i in list]):
    continue

Upvotes: 0

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