Reputation: 818
Well, I'm coding the OnPaint event for my own control and it is very nescessary for me to make it pixel-accurate.
I've got a little problem with borders of rectangles.
See picture:
removed dead ImageShack link
These two rectangles were drawn with the same location and size parameters, but using different size of the pen. See what happend? When border became larger it has eaten the free space before the rectangle (on the left).
I wonder if there is some kind of property which makes border be drawn inside of the rectangle, so that the distance to rectangle will always be the same. Thanks.
Upvotes: 35
Views: 56915
Reputation: 18429
You can do this by specifying PenAlignment
Pen pen = new Pen(Color.Black, 2);
pen.Alignment = PenAlignment.Inset; //<-- this
g.DrawRectangle(pen, rect);
Upvotes: 70
Reputation: 158309
If you want the outer bounds of the rectangle to be constrained in all directions you will need to recalculate it in relation to the pen width:
private void DrawRectangle(Graphics g, Rectangle rect, float penWidth)
{
using (Pen pen = new Pen(SystemColors.ControlDark, penWidth))
{
float shrinkAmount = pen.Width / 2;
g.DrawRectangle(
pen,
rect.X + shrinkAmount, // move half a pen-width to the right
rect.Y + shrinkAmount, // move half a pen-width to the down
rect.Width - penWidth, // shrink width with one pen-width
rect.Height - penWidth); // shrink height with one pen-width
}
}
Upvotes: 10
Reputation: 147280
This isn't a direct answer to the question, but you might want to consider using the ControlPaint.DrawBorder
method. You can specify the border style, colour, and various other properties. I also believe it handles adjusting the margins for you.
Upvotes: 2
Reputation: 7200
I guess not... but you may move the drawing position half the pen size to the bottom right
Upvotes: 0