Reputation: 4909
I have some code like this:
function switch_tabs(obj) {
$('.tab-content').hide();
$('.tabs a').removeClass("selected");
var id = obj.attr("rel");
$('#' + id).show();
obj.addClass("selected");
}
The show function adds display:block
. But I would like to add display:inline-block
instead of block.
Upvotes: 173
Views: 211288
Reputation: 1
add a css property to the element
#tab {
display:inline-block;
}
in the JS, add and remove "hide" class
$("#" + id).addClass("hide");
$("#" + id).removeClass("hide");
Upvotes: 0
Reputation: 424
<style>
.demo-ele{display:inline-block}
</style>
<div class="demo-ele" style="display:none">...</div>
<script>
$(".demo-ele").show(1000);//hide first, show with inline-block
<script>
Upvotes: 2
Reputation: 1
The best .let it's parent display :inline-block
or add a parent div
what CSS only have display :inline-block
.
Upvotes: 0
Reputation: 21
I think you want both the animation and to set the display property at the end. In that case you better use show()
callback as shown below
$("#my_obj").show(400,function() {
$("#my_obj").css("display","inline-block")
}) ;
This way you will achieve both the results.
Upvotes: 2
Reputation: 709
actually jQuery simply clears the value of the 'display' property, and doesn't set it to 'block' (see internal implementation of jQuery.showHide()) -
function showHide(elements, show) {
var display, elem, hidden,
...
if (show) {
// Reset the inline display of this element to learn if it is
// being hidden by cascaded rules or not
if (!values[index] && display === "none") {
elem.style.display = "";
}
...
if (!show || elem.style.display === "none" || elem.style.display === "") {
elem.style.display = show ? values[index] || "" : "none";
}
}
Please note that you can override $.fn.show()/$.fn.hide(); storing original display in element itself when hiding (e.g. as an attribute or in the $.data()); and then applying it back again when showing.
Also, using css important! will probably not work here - since setting a style inline is usually stronger than any other rule
Upvotes: 1
Reputation: 710
Use css() just after show() or fadeIn() like this:
$('div.className').fadeIn().css('display', 'inline-block');
Upvotes: 11
Reputation: 329
Razz's solution would work for the .hide()
and .show()
methods but would not work for the .toggle()
method.
Depending upon the scenario, having a css class .inline_block { display: inline-block; }
and calling $(element).toggleClass('inline_block')
solves the problem for me.
Upvotes: 5
Reputation: 59
I did that
function showPanels() {
$('.panels').show("slow");
$('.panels').css('display','inline-block');
}
works like a charm.
Upvotes: 5
Reputation: 11
Best way is to add !important suffix to the selector .
Example:
#selector{
display: inline-block !important;
}
Upvotes: -5
Reputation: 4015
Instead of show
, try to use CSS to hide and show the content.
function switch_tabs(obj) {
$('.tab-content').css('display', 'none'); // you could still use `.hide()` here
$('.tabs a').removeClass("selected");
var id = obj.attr("rel");
$('#' + id).css('display', 'inline-block');
obj.addClass("selected");
}
Upvotes: 228
Reputation: 7546
Setting the CSS property after you have used .show()
should work. Maybe you are targeting the wrong element on your HTML page.
$('#foo').css('display', 'inline-block');
But if you are not using any effects of .show(), .hide()
why don't you set those CSS properties manually like:
$('#foo').css('display','none');
$('#foo').css('display','inline-block');
Upvotes: 39