Reputation: 107
I'm trying to use NSNumberFormatter
and I would like to use: -setPositiveFormat
to customize a format.
I want to transform 121212.12
to 12.12E+04
I have to use 9 digits and 2 decimals
I'm closed to my goal with:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setFormatterBehavior:NSFoundationVersionNumber10_4]; // iOS supports only the modern 10.4+ behavior
[formatter setNumberStyle:NSNumberFormatterScientificStyle];
[formatter setMinimumFractionDigits:numberOfDecimalDigits];
[formatter setPositiveFormat:@"#.#E+00"];
[formatter setFormatWidth:9]; // set width
[formatter setPaddingCharacter:@"x"]; // choice padding Char
NSString *convertNumber = [formatter stringFromNumber:number];
return convertNumber;
But it's not working...
Customize a format like:
[formatter setPositiveFormat:@"#.#E+00]; // my string is from my intuition ....
Is it a solution ?
2nd question : I'm not understanding what #
means? Also 00
in the string ? (I can't find answer in Doc)
Thanks !
Upvotes: 2
Views: 3387
Reputation: 27536
I understand that you want your formatted number to have exactly the following format: (2 digits).(2 digits)E+(2 digits)
You can configure your NSNumberFormatter
as follows:
NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setPositiveFormat:@"00.00E+00"];
NSNumber *number = [NSNumber numberWithFloat:121212.12];
NSString *convertNumber = [formatter stringFromNumber:number];
As for the meaning of 0
and #
have a look at this link.
Upvotes: 4