CODEWITHSUNDEEP
c#liststring
bitcycle
bitcycle

Reputation: 7792

Copying a portion of a list to a new list

Hey all. Is there a way to copy only a portion of a single (or better yet, a two) dimensional list of strings into a new temporary list of strings?

Upvotes: 16

Views: 22793

Answers (3)

Mike Dinescu
Mike Dinescu

Reputation: 55750

I'm not sure I get the question, but I would look at the Array.Copy function (if by lists of strings you're referring to arrays)

Here is an example using C# in the .NET 2.0 Framework:

String[] listOfStrings = new String[7] 
                              {"abc","def","ghi","jkl","mno","pqr","stu"};
String[] newListOfStrings = new String[3];

// copy the three strings starting with "ghi" 
Array.Copy(listOfStrings, 2, newListOfStrings, 0, 3);

// newListOfStrings will now contains {"ghi","jkl","mno"}

Upvotes: 1

Dave Bauman
Dave Bauman

Reputation: 9698

FindAll will let you write a Predicate to determine which strings to copy:

List<string> list = new List<string>();
list.Add("one");
list.Add("two");
list.Add("three");

List<string> copyList = list.FindAll(
    s => s.Length >= 5
);

copyList.ForEach(s => Console.WriteLine(s));

This prints out "three", because it is 5 or more characters long. The others are ignored.

Upvotes: -1

Jon Skeet
Jon Skeet

Reputation: 1502276

Even though LINQ does make this easy and more general than just lists (using Skip and Take), List<T> has the GetRange method which makes it a breeze:

List<string> newList = oldList.GetRange(index, count);

(Where index is the index of the first element to copy, and count is how many items to copy.)

When you say "two dimensional list of strings" - do you mean an array? If so, do you mean a jagged array (string[][]) or a rectangular array (string[,])?

Upvotes: 40

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