CODEWITHSUNDEEP
pythonunicodepython-2.7
Dr Hydralisk
Dr Hydralisk

Reputation: 33

comparing Unicode strings?

Basically what I am trying to do is compare "✔" == "✔" in Python (2.7). But I keep receiving this error, SyntaxError: Non-ASCII character '\xe2'. I read the Python docs but the whole Unicode, encoding, and decoding thing is confusing me a lot..

EDIT

I fixed the problem by comparing what should be the ✔ against \u2714, which is check marks character code (I think that is what you would call it?).

Upvotes: 0

Views: 902

Answers (2)

Jakub Roztocil
Jakub Roztocil

Reputation: 16232

You haven't specified what charset the file uses, so Python defaults to ASCII and fails with a SyntaxError as soon as it encounters the unicode characters. Adding this at the very beginning of the file should fix that:

# coding:utf-8

More info here: http://www.python.org/dev/peps/pep-0263/

Upvotes: 6

avasal
avasal

Reputation: 14854

Works at my side:

[avasal@avasal]$ python
Python 2.7 (r27:82500, Sep 16 2010, 18:02:00) 
[GCC 4.5.1 20100907 (Red Hat 4.5.1-3)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> "✔" == "✔"
True
>>> u"✔" == u"✔"
True
>>>

Upvotes: 0

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