Reputation: 113
i was searching in stackoverflow and the only thing i got is something like this. I want to do with this code
<select class="input_select" name='nombre_compania'><?
msqlcon_catering(); //which is the function i made that connects to the database
$query = "SELECT * FROM compania ORDER BY id DESC";
$result = mysql_query($query);
while ($r = mysql_fetch_array($result))
{
echo "<option value=\"". $r['id'] ."\">". $r['compania_nombre'] ."</option>";
}?>
</select>
That when the user select a certain option, stay selected after submitting the form if he misses something or he put something wrong. Thanks
Upvotes: 1
Views: 1038
Reputation: 18833
<?php
$selected = null;
if(isset($_POST['nombre_compania']))
{
$selected = $_POST['nombre_compania'];
}
?>
<select class="input_select" name='nombre_compania'><?
msqlcon_catering(); //which is the function i made that connects to the database
$query = "SELECT * FROM compania ORDER BY id DESC";
$result = mysql_query($query);
while ($r = mysql_fetch_array($result))
{
echo "<option value=\"". $r['id'] ."\" ".($selected == $r['id'] ? 'selected=\"selected\"': '').">". $r['compania_nombre'] ."</option>";
}?>
</select>
Upvotes: 1
Reputation: 46040
<select class="input_select" name='nombre_compania'><?
msqlcon_catering(); //which is the function i made that connects to the database
$query = "SELECT * FROM compania ORDER BY id DESC";
$result = mysql_query($query);
while ($r = mysql_fetch_array($result))
{
echo "<option value=\"". $r['id'] ."\"" . (isset($_REQUEST["nombre_compania"]) && $_REQUEST["nombre_compania"] == $r['id'] ? " selected='selected'" : "") . ">". $r['compania_nombre'] ."</option>";
}?>
</select>
Upvotes: 0