CODEWITHSUNDEEP
phpquery-string
HandiworkNYC.com
HandiworkNYC.com

Reputation: 11124

PHP: Remove all but one query string variables

Suppose I have the following, which is the current url:

http://myurl.com/locations/?s=bricks&style=funky-quirky+rustic&feature=floors-concrete+kitchen+bathroom

How would I remove all parameters except S using PHP? In other words, just leaving: http://myurl.com/locations/?s=bricks The other parameters will always be Style, Type, Feature, and Area, and some or all of them may be present.

Thanks!

Upvotes: 0

Views: 1540

Answers (5)

Alex Coplan
Alex Coplan

Reputation: 13371

If you know that s will always be the first parameter, then you can simply do:

$url = "http://myurl.com/locations/?s=bricks&style=funky-quirky+rustic&feature=floors-concrete+kitchen+bathroom";
$split = explode('&',$url);
echo $split[0];

However, if the position of s in the parameters is unkown, then you can do this:

$url = "http://myurl.com/locations/?s=bricks&style=funky-quirky+rustic&feature=floors-concrete+kitchen+bathroom";
$split = explode('?',$url);
parse_str($split[1],$params);
echo $split[0].'?s='.$params['s'];

Upvotes: 1

Mike
Mike

Reputation: 24413

parse_str(parse_url($url, PHP_URL_QUERY), $query);
$newurl = 'http://myurl.com/locations/?s=' . $query['s'];

Upvotes: 1

simshaun
simshaun

Reputation: 21476

if ( isset($_GET['s']) && count($_GET) > 1 ) {
    header('Location: ?s='. rawurlencode($_GET['s']));
    exit;
}

Edited to somewhat appease Jon.

Upvotes: 1

Guilherme Viebig
Guilherme Viebig

Reputation: 6930

You can achieve this in several different manners.

I will show you the best standard I ever faced to work with urls:

$originUrl = parse_url('http://myurl.com/locations/?s=bricks&style=funky-quirky+rustic&feature=floors-concrete+kitchen+bathroom'); 
parse_str($originUrl['query'], $queryString);
echo $newUrl = $originUrl['scheme'].'://'.$originUrl['host'].$originUrl['path'].'?s='.$queryString['s'];

Good Luck!

Upvotes: 1

Jon
Jon

Reputation: 437854

Not much in the way of error checking, but if s is guaranteed to exist this will work:

list($base, $query) = explode('?', $url);
parse_str($query, $vars);
$result = $base.'?s='.rawurlencode($vars['s']);

It will also work no matter in what position s appears in the query string. I 'm doing a minimal initial "parsing" step with explode, but if that doesn't feel right you can always bring in the big guns and go with parse_url instead at the expense of being much more verbose.

Upvotes: 1

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