Reputation: 868
I'm currently trying to send data via POST to a server, and the server is handling the data and appends it to a JSON file. I'm currently getting a 422 error and I've been receiving it for a while now. My question is: How do I receive that JSON error itself in Java so that I can see what the error is. All I'm seeing is a HttpResponseException and it doesn't give me anything else. Thanks for the time and help in advance.
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(mPath);
// Add your data
try
{
List nameValuePairs = new ArrayList(4);
httppost.setHeader("Authorization", Base64.encodeToString(new StringBuilder(bundleId).append(":").append(apiKey).toString().getBytes("UTF-8"), Base64.URL_SAFE|Base64.NO_WRAP));
nameValuePairs.add(new BasicNameValuePair("state", "CA"));
nameValuePairs.add(new BasicNameValuePair("city", "AndDev is Cool!"));
nameValuePairs.add(new BasicNameValuePair("body", "dsads is assrawstjljalsdfljasldflkasjdfjasldjflasjdflkjaslfggddsfgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfdsgfddjflaskjdfkasjdlfkjasldfkjalskdjfajasldfkasdlfjasljdflajsdfjasdjflaskjdflaksjdfljasldfkjasljdflajsasdlfkjasldfkjlas!"));
nameValuePairs.add(new BasicNameValuePair("title", "dsaghhhe fd!"));
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
// Execute HTTP Post Request
//HttpResponse response = httpclient.execute(httppost);
//int status = response.getStatusLine().getStatusCode();
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String responseBody = httpclient.execute(httppost, responseHandler);
Log.v(TAG, "response: " + responseBody);
//JSONObject response = new JSONObject(responseBody);
int f = 0;
}
catch(HttpResponseException e)
{
Log.e(TAG, e.getLocalizedMessage());
Log.e(TAG, e.getMessage());
e.printStackTrace();
}
Upvotes: 0
Views: 1354
Reputation: 68187
you may send your parameters more conveniently by using predefined Json class as below:
String jsonParam = null;
try{
JSONObject param = new JSONObject();
param.put("state", "CA");
param.put("city", "AndDev is Cool!");
//and so on with other parameters
jsonParam = param.toString();
}
catch (Exception e) {
// TODO: handle exception
}
and set the post entity as:
if(jsonParam != null)
httppost.setEntity(new StringEntity(jsonParam, HTTP.UTF_8));
Upvotes: 2
Reputation: 32271
422 error says: Unprocessable Entity - The request was well-formed but was unable to be followed due to semantic errors
You got a problem with UrlEncodedFormEntity
Upvotes: 1