CODEWITHSUNDEEP
bash
qdii
qdii

Reputation: 12973

How come this bash script can write 'a'?

#/bin/bash

PATH_GSUTIL=""
[ -f "$PATH_GSUTIL"/gsutil ] || (echo "$PATH_GSUTIL does not contain 'gsutil'" && exit)
echo a

I would expect it to quit on exit. How come it goes on and executes the next line?

Upvotes: 0

Views: 62

Answers (2)

A.H.
A.H.

Reputation: 66283

Building upon unwind's answer: () creates a subshell which then executes the exit. You can use the {} (with some more whitespace required around the { and }). That will do the job in your case, because the exit will then be executed by the outer shell.

Upvotes: 1

unwind
unwind

Reputation: 400079

The () command grouping operator creates a sub-shell, which is what you're exiting from.

Upvotes: 2

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