CODEWITHSUNDEEP
tomcatresteasy
eshayne
eshayne

Reputation: 935

404 response on simple RESTeasy example with Tomcat

I am trying to put together a very simple "hello world" service with Tomcat and RESTeasy. But when I try to test it, all I get are 404 responses from Tomcat. Here are the steps I followed, hopefully someone can point out where I went wrong:

  1. Created a new Dynamic Web Project in Eclipse. The Target Runtime is set for Apache Tomcat 7.0, Dynamic web module version 3.0.

  2. Copied all of the jar files from resteasy-jaxrs-2.3.1.GA-all.zip into WEB-INF\lib

  3. Added one class:

    package com.eshayne.resteasy;

    import javax.ws.rs.GET;
    import javax.ws.rs.Path;
    import javax.ws.rs.Produces;
    import javax.ws.rs.core.MediaType;

    @Path("/sampleservice")
    public class SampleService {
        @GET
        @Path("/hello")
        @Produces(MediaType.TEXT_HTML)
        public String hello()
        {
            return "hello world";
        }
    }
  1. Set web.xml to:
    <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0" metadata-complete="true">
        <display-name>resteasy</display-name>

        <listener>
            <listener-class>org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap</listener-class>
        </listener>

        <servlet>
            <servlet-name>Resteasy</servlet-name>
            <servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
        </servlet>

        <servlet-mapping>
            <servlet-name>Resteasy</servlet-name>
            <url-pattern>/restful-services/*</url-pattern>
        </servlet-mapping>

        <context-param>
            <param-name>resteasy.scan</param-name>
            <param-value>true</param-value>
        </context-param>

        <context-param>
            <param-name>resteasy.servlet.mapping.prefix</param-name>
            <param-value>/restful-services</param-value>
        </context-param>
    </web-app>

  1. Added the new project to Tomcat and restarted Tomcat (within Eclipse)

  2. Opened a web browser and requested /resteasy/restful-services/sampleservice/hello

This returns a 404 response from Tomcat with the description:

The requested resource (/resteasy/restful-services/sampleservice/hello) is not available.

What am I missing?

Upvotes: 2

Views: 6906

Answers (3)

Beryllium
Beryllium

Reputation: 12988

A quote from RESTEasy tutorial: The URL to access a resource consists of

<web context>/<class level @Path>/<Method level @Path>

For example, if you deploy demo.war, it looks like this: 

http://localhost:8080/demo/sampleservice/hello

And there must be a servlet-mapping in web.xml, for example:

<servlet-mapping>
        <servlet-name>Resteasy</servlet-name>
        <url-pattern>/sampleservice/*</url-pattern>
</servlet-mapping>

Upvotes: 1

eshayne
eshayne

Reputation: 935

It turns out that the URL for a given resource is not in fact <display-name>/<servlet-mapping>/<class Path>/<method Path>. It is actually <project-name>/<servlet-mapping>/<class Path>/<method Path>.

Upvotes: 1

tomdee
tomdee

Reputation: 2439

Have you tried visiting variations on the URL - e.g. /restful-services/sampleservice/hello

Upvotes: 1

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