CODEWITHSUNDEEP
mysqlcmysql-error-1064
Bag Dev
Bag Dev

Reputation: 185

MYSQL API in C - linux

I can't get the following code to work. It's working with normal select or insert, but when I try to insert a variable to it it didn't work. Can some let me know please what's wrong here?

Please note that the output is below.

int main(int argc, char **argv)
{

  MYSQL *conn;
  char str[100] = "test";
  conn = mysql_init(NULL);

  char stmt_buf[100];
  sprintf (stmt_buf, "insert into test values ('%s')", str);

  printf("\n%s\n",stmt_buf);

  mysql_query (conn, stmt_buf);
  mysql_close(conn);
  return 0;
}

~$./version

insert into test values ('test')
Segmentation fault

Upvotes: 0

Views: 1536

Answers (2)

Shiplu Mokaddim
Shiplu Mokaddim

Reputation: 57650

I didn't see you are connected to database by mysql_real_connect also there is no mysql_select_db and mysql_exec_sql call.

Here is an example for you.

int main(int argc, char **argv)
{
    MYSQL mysql;
    char stmt_buf[100];
    if (mysql_init(&mysql) == NULL) {
        printf("Can not initialize");
        exit(1);
    }
    if (!mysql_real_connect
        (&mysql, "localhost", "USERNAME", "PASSWORD", NULL, 0, NULL, 0)) {
        mysql_error(&mysql);
        exit(1);
    }

    if (mysql_select_db(&mysql, "DATABASENAME")) {
        mysql_error(&mysql);
        exit(1);
    }

    sprintf(stmt_buf, "insert into test values ('%s')", "test");

    if (mysql_exec_sql(&mysql, stmt_buf))
        mysql_error(&mysql));

    mysql_close(&mysql);
}

Upvotes: 1

Dietrich Epp
Dietrich Epp

Reputation: 213318

You don't do any error checking. My guess is conn == NULL.

For the record, don't use sprintf ever. Use snprintf instead, that is, if you're okay with SQL injections.

Upvotes: 2

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