CODEWITHSUNDEEP
formattingioerlang
TheSquad
TheSquad

Reputation: 7506

Erlang: How to transform a decimale into a Hex string filled with zeros

I would like to transform 42 (Base 10) into 000002A (Base 16) in Erlang...

I have found some pointers on the web : 

io:format("~8..0B~n", [42]) -> 00000042

And

io:format("~.16B~n", [42]) -> 2A

But I cannot seems to find how to do both at the same time, I have tried : 

io:format("~8..0.16B~n", [42])

Which seemed to be the logical thing, but it is not, it gives me an error.

Thanks.

Upvotes: 3

Views: 2109

Answers (2)

Anatolii Kosorukov
Anatolii Kosorukov

Reputation: 960

Transform 42 (Base 10) into "000002A" (Base 16) in Erlang:

> io_lib:format("~8.16.0B", [42]).
> "0000002A"

Upvotes: 0

butter71
butter71

Reputation: 2723

io:format("~8.16.0B~n", [42]).
0000002A

basically, it's ~F.P.Pad where:

  • F = field width
  • P = precsion
  • Pad = pad character

see the full io:format docs

Upvotes: 9

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