Reputation: 21
I want to list all teams, then count how many times each team appears in my second table. Some users are not in the second table, so the count would be zero. The problem is when I use the count function it only lists users that are in the second table. How do I count, and list 0 if they dont appear in second table?
$query = "SELECT t.id as id, t.t_name as name, t.t_city as city, (count(pd.rs)) as pd FROM #__bl_regions as r, #__bl_teams as t, #__bl_paid as pd WHERE t.id != 0 AND t.id != 1 AND (t.id IN($teams)) AND r.id = ".$t_id." AND pd.rs = 1 AND pd.t_id = ".$t_id." ORDER BY t.t_name";
$db->setQuery($query);
$players = $db->loadObjectList();
Tried Left Join
Ok, so because I am including 3 tables I believe I have to use 2 queries. Same thing is still happening, only listing schools with count. #__bl_paid is the table I want to count, #__bl_teams is the table I want to list all.
$query = "SELECT t.id as id FROM #__bl_regions as r, #__bl_teams as t WHERE t.id != 0 AND t.id != 1 AND (t.id IN($teams)) AND r.id = ".$t_id." ORDER BY t.t_name";
$db->setQuery($query);
$players1 = $db->loadResultArray();
if ($players1){
$players2 = implode(",",$players1);
}else{
$players2 = 0;
}
$query = "SELECT t.id as id, t.t_name as name, t.t_city as city, coalesce((count(pd.rs)),0) as pdc FROM #__bl_paid as pd LEFT JOIN #__bl_teams as t ON pd.t_id = t.id WHERE (t.id IN($players2)) ORDER BY t.t_name";
$db->setQuery($query);
$players = $db->loadObjectList();
Upvotes: 0
Views: 1319
Reputation: 49085
You need two pieces to get what you want:
left join
is the typical MySQL version usedcoalesce
An inner join
drops rows that don't have matches in the other table; a left join
is similar to an inner join
, but preserves all the rows in the left table, and supplies columns with null if there's no matching row in the right table.
Here's an example:
select column1, coalesce(column2, 0) as `newcolumn2`
from lefttable
left join righttable
on lefttable.something = righttable.something
What this will do: whenever column2
is null, it will be replaced with 0.
Upvotes: 1