CODEWITHSUNDEEP
objective-ciosnsinteger
Ahsan
Ahsan

Reputation: 2982

How to compare two NSInteger?

How do we compare two NSInteger numbers ? I have two NSIntegers and comparing them the regular way wasnt working.

if (NSIntegerNumber1 >= NSIntegerNumber2) {
    //do something
}

Eventhough, the first value was 13 and the second value was 17, the if loop is executing

Any idea ?

Upvotes: 8

Views: 32288

Answers (4)

Rama Rao
Rama Rao

Reputation: 1033

NSInteger int1;
NSInteger int2;

int1 = 13;
int2 = 17;

if (int1 > int2)
{
    NSLog(@"works");
}

Upvotes: 9

justin
justin

Reputation: 104728

NSInteger is just a typedef for a builtin integral type (e.g. int or long).

It is safe to compare using a == b.

Other common operators behave predictably: !=, <=, <, >= et al.

Finally, NSInteger's underlying type varies by platform/architecture. It is not safe to assume it will always be 32 or 64 bit.

Upvotes: 13

wizH
wizH

Reputation: 488

When comparing integers, using this, would work just fine:

int a = 5;
int b = 7;

if (a < b) {

NSLog(@"%d is smaller than %d" a, b);   

}

Upvotes: 2

lnafziger
lnafziger

Reputation: 25740

Well, since you have Integer and Number in the name, you might have declared the two values as NSNumber instead of NSInteger. If so, then you need to do the following:

 if ([NSIntegerNumber1 intValue] >= [NSIntegerNumber2 intValue]) {
      // do something
 }

Otherwise it should work as is!

Upvotes: 12

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