CODEWITHSUNDEEP
makefile
Kristina
Kristina

Reputation: 903

Use directory path of target in list of prerequisites in Makefile

I wrote a script that takes in two files ending in .cfg and outputs a file ending in .cmp. I want to include this in my Makefile because a few source code files depend on this .cmp file.

In my Makefile, I want to do this:

%.cmp: %.cfg $(dir %)/default.cfg
    ./compare.pl $^ $@

There are two dependencies to generate the .cmp file. First is a .cfg file with the same name, and second is a .cfg file which is always named default. Both .cfg files and the output .cmp file will be in the same directory.

Is there a way to grab the directory path of the target and use it with the prereqs?

Upvotes: 4

Views: 2236

Answers (1)

Eldar Abusalimov
Eldar Abusalimov

Reputation: 25483

I guess Secondary Expansion is probably what you're looking for:

.SECONDEXPANSION:
%.cmp: %.cfg $$(dir %)default.cfg
    ./compare.pl $^ $@

Also note the absence of slash after $$(dir %), dir function always append one to the resulting value.

Upvotes: 4

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