CODEWITHSUNDEEP
rubyregex
Matt Elhotiby
Matt Elhotiby

Reputation: 44066

How does this work in ruby?

Ok so i dont understand regex checker works in ruby

=~

1.9.2p290 :009 > url = "/myurl"
 => "/myurl" 
1.9.2p290 :010 > url =~ %r{^/.*/found/\d+$}i
 => nil 
1.9.2p290 :011 > url = "/myurl/found/1"
 => "/myurl/found/1" 
1.9.2p290 :012 > url =~ %r{^/.*/found/\d+$}i
 => 0

It seems to return a value of something if found otherwise it returns nil ...but i dont know for sure ....where is the documentation for this anywhere...i tried to google for this and no luck at all...any help would be appreciated

Upvotes: 0

Views: 113

Answers (1)

sawa
sawa

Reputation: 168081

When it matches, it returns the position of the beginning of the match. Otherwise, returns nil. The 0 in your last example means that the substring that matched the regex starts from position 0 of the original string.

Upvotes: 3

Related Questions